Exercise · ZW-OPEN-SET-IN-A-METRIC-SPACE-010 · ★★★ Advanced

Let \(X=(0,1]\) with the usual distance. Is \((1/2,1]\) open in the space \(X\)?

Choose one option.

Show answer
  • B. Yes, because in \(X\) we have \(B(1,1/2)=(1/2,1]\)

Explanation

Inside \(X\), \(B(1,1/2)=\{y\in(0,1]: |y-1|<1/2\}=(1/2,1]\), and the other points have small balls inside. Openness depends on the ambient space \(X\), not on \(\mathbb{R}\).

Study General topology in ZWMath →

Review the concept: Open set in a metric space

A subset \(U\) of a metric space \((X,d)\) is open if every point \(x\in U\) is the center of some open ball \(B(x,r)\) contained in \(U\).

\[\forall x\in U\ \ \exists r>0:\ B(x,r)\subseteq U\]

More practice problems: open set in a metric space

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