Exercise · ZW-OPEN-SET-IN-A-METRIC-SPACE-010 · ★★★ Advanced
Let \(X=(0,1]\) with the usual distance. Is \((1/2,1]\) open in the space \(X\)?
Choose one option.
A No, because \(1\) is an endpoint B Yes, because in \(X\) we have \(B(1,1/2)=(1/2,1]\) C No, because it is not open in \(\mathbb{R}\) D Yes, but only because \(X\) is closed
Show answer B. Yes, because in \(X\) we have \(B(1,1/2)=(1/2,1]\)
← Back to the question
Explanation Inside \(X\), \(B(1,1/2)=\{y\in(0,1]: |y-1|<1/2\}=(1/2,1]\), and the other points have small balls inside. Openness depends on the ambient space \(X\), not on \(\mathbb{R}\).
A subset \(U\) of a metric space \((X,d)\) is open if every point \(x\in U\) is the center of some open ball \(B(x,r)\) contained in \(U\).
\[\forall x\in U\ \ \exists r>0:\ B(x,r)\subseteq U\]
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