Exercise · ZW-PROXIMAL-OPERATOR-003 · ★☆☆ Basic

What is the proximal operator at \( x=0.5 \) when \( f(u)=|u| \)?

Choose one option.

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  • B. \( 0 \)

Explanation

Soft-thresholding with \( \lambda=1 \) sets any \( x \) with \( |x|\le 1 \) to zero, so the result is \( 0 \). The option \( 0.5 \) ignores the norm penalty.

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Review the concept: Proximal operator

The proximal operator of a convex function \( f \) maps each point \( x \) to the unique minimizer of \( f(u)+\frac{1}{2}\|u-x\|^2 \).

\[\operatorname{prox}_{f}(x)=\arg\min_{u}\left\{f(u)+\tfrac{1}{2}\|u-x\|^2\right\}\]

More practice problems: proximal operator

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