Exercise · ZW-QUOTIENT-RULE-004 · ★★☆ Intermediate

Differentiate \(f(x)=\frac{x^{2} + 1}{x - 1}\).

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  • D. \(\frac{x^{2} - 2 x - 1}{\left(x - 1\right)^{2}}\)

Explanation

With \(u=x^{2} + 1\) and \(v=x - 1\): \(u'=2 x\), \(v'=1\). Then \(\left(\dfrac{u}{v}\right)'=\dfrac{u'v-uv'}{v^{2}}=\frac{x^{2} - 2 x - 1}{\left(x - 1\right)^{2}}\).

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Review the concept: Quotient rule

The derivative of a quotient \(\frac{f}{g}\), with \(g\ne0\), is \(\frac{f^{\prime}g-fg^{\prime}}{g^2}\).

\[\left(\frac{f}{g}\right)'=\frac{f'g-f\,g'}{g^{2}}\]

More practice problems: quotient rule

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