Exercise · ZW-RANK-NULLITY-THEOREM-005 · ★☆☆ Basic

What is the dimension of the image of an injective linear map \(T:\mathbb{R}^3\to\mathbb{R}^5\)?

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  • C. \(3\)

Explanation

Injective means the kernel is \(\{0\}\), of dimension \(0\), so \(\dim\operatorname{Im}T=3-0=3\), not \(5\).

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Review the concept: Rank–nullity theorem

For a linear transformation \(T\) with finite-dimensional domain \(V\), the dimension of the kernel plus that of the image equals the dimension of \(V\).

\[\dim V=\dim\ker T+\dim\operatorname{Im}T\]

More practice problems: rank–nullity theorem

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