Exercise · ZW-REAL-INTEGRAL-BY-RESIDUES-003 · ★☆☆ Basic

For \(\int_{-\infty}^{\infty}\frac{dx}{x^{2}+9}\), which poles of \(1/(z^2+9)\) enter the sum of residues?

Choose one option.

Show answer
  • A. Only \(3i\)

Explanation

We close in the upper half-plane, which contains \(3i\) but not \(-3i\). The result is \(2\pi i\cdot\frac{1}{6i}=\pi/3\).

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Review the concept: Real integral by residues

A method to compute \(\int_{-\infty}^{\infty} f(x)\,dx\) with \(f\) rational: close the real axis with a semicircle in the upper half-plane and apply the residue theorem.

\[\int_{-\infty}^{\infty} f(x)\,dx=2\pi i\sum_{\operatorname{Im}z_k>0}\operatorname{Res}(f,z_k)\]

More practice problems: real integral by residues

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