Exercise · ZW-RIESZ-FISCHER-THEOREM-001 · ★☆☆ Basic

Which space does the Riesz-Fischer theorem guarantee is complete?

Choose one option.

Show answer
  • A. \( L^p(\mu) \) for \( 1 \le p \le \infty \)

Explanation

The theorem concerns the \( L^p \) spaces of measurable function classes. The rationals do not form a complete space under the usual norm.

Study Measure theory and integration in ZWMath →

Review the concept: Riesz–Fischer theorem

The Riesz-Fischer theorem states that the space \( L^p(\mu) \) is complete for \( 1 \le p \le \infty \), that is, every Cauchy sequence in it converges to an element of \( L^p(\mu) \).

\[\lim_{n,m\to\infty}\|f_n-f_m\|_p=0 \implies \exists f\in L^p:\ \|f_n-f\|_p\to 0\]

More practice problems: riesz–fischer theorem

ZW-RIESZ-FISCHER-THEOREM-002 →