Exercise · ZW-RIESZ-FISCHER-THEOREM-008 · ★★☆ Intermediate

What is the limit in \( L^1([0,1]) \) of \( f_n=\mathbf{1}_{(0,1/n)} \)?

Choose one option.

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  • B. The zero function

Explanation

Since \( \mu((0,1/n))=1/n \to 0 \), the integral of \( f_n \) tends to zero and the limit is the zero function.

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Review the concept: Riesz–Fischer theorem

The Riesz-Fischer theorem states that the space \( L^p(\mu) \) is complete for \( 1 \le p \le \infty \), that is, every Cauchy sequence in it converges to an element of \( L^p(\mu) \).

\[\lim_{n,m\to\infty}\|f_n-f_m\|_p=0 \implies \exists f\in L^p:\ \|f_n-f\|_p\to 0\]

More practice problems: riesz–fischer theorem

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