Exercise · ZW-SECOND-ORDER-LINEAR-EQUATION-010 · ★★★ Advanced

If \(y_1=e^{t}\) solves \(y''-y=0\), which of these functions also solves it?

Choose one option.

Show answer
  • D. \(e^{-t}\)

Explanation

With \(y=e^{-t}\): \(y''-y=e^{-t}-e^{-t}=0\). \(e^{2t}\) gives \(3e^{2t}\), \(e^t+1\) gives \(-1\), and the constant \(1\) gives \(-1\).

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Review the concept: Second-order linear equation

It is a second-order differential equation, linear in the unknown \(y\) and its derivatives, whose coefficients \(p\), \(q\) and term \(g\) depend only on \(t\).

\[y''+p(t)\,y'+q(t)\,y=g(t)\]

More practice problems: second-order linear equation

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