Exercise · ZW-SUBSPACE-TOPOLOGY-004 · ★☆☆ Basic
With the same \(X\), what is the subspace topology on \(A=\{1,2\}\)?
Choose one option.
A \(\{\varnothing,\{1\}\}\) B \(\{\varnothing,\{1\},A\}\) C \(\{\varnothing,\{1\},\{2\},A\}\) D \(\{\varnothing,A\}\)
Show answer B. \(\{\varnothing,\{1\},A\}\)
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Explanation The intersections with \(A\) are \(\varnothing,\{1\},\varnothing,\{1\},\{1,2\},\{1,2\}\). The topology is \(\{\varnothing,\{1\},A\}\); keeping only the open sets of \(X\) contained in \(A\) is not enough (\(A\) itself comes from \(\{1,2,3\}\cap A\)).
The topology \(\mathcal{T}_A\) on a subset \(A\) of a topological space \((X,\mathcal{T})\) whose open sets are the intersections of \(A\) with the open sets \(U\) of \(X\).
\[\mathcal{T}_A=\{A\cap U:\ U\in\mathcal{T}\}\]
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