Exercise · ZW-SURFACE-INTEGRAL-003 · ★☆☆ Basic

The area of the cylinder \(x^2+y^2=1\), \(0\le z\le3\) (without caps) is:

Choose one option.

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  • D. \(6\pi\)

Explanation

With \(\mathbf r=\langle\cos u,\sin u,v\rangle\), \(\lVert\mathbf r_u\times\mathbf r_v\rVert=1\) and \(D=[0,2\pi]\times[0,3]\): the area is \(2\pi\cdot3=6\pi\).

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Review the concept: Surface integral

The surface integral of a function \(f\) over a surface \(S\), parametrized by \(\mathbf r\) over a region \(D\), adds up the values of \(f\) weighted by the area of each piece of \(S\).

\[\iint_S f\,dS=\iint_D f(\mathbf r(u,v))\,\lVert\mathbf r_u\times\mathbf r_v\rVert\,du\,dv\]

More practice problems: surface integral

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