Exercise · ZW-TANGENT-LINE-005 · ★☆☆ Basic

Find the equation of the tangent line to \(f(x)=e^{x}\) at \(x=0\).

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  • C. \(y = x + 1\)

Explanation

Compute \(f(0)=1\) and \(f'(x)=e^{x}\), so \(f'(0)=1\). The line is \(y-f(0)=f'(0)(x-0)\), that is, \(y = x + 1\).

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Review the concept: Tangent line

The tangent line to the graph of \(f\) at the point \((a,f(a))\) is the line through that point with slope \(f^{\prime}(a)\). It is the best linear approximation of \(f\) near \(a\).

\[y-f(a)=f'(a)\,(x-a)\]

More practice problems: tangent line

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