Exercise · ZW-TANGENT-LINE-003 · ★★☆ Intermediate

Find the equation of the tangent line to \(f(x)=\sqrt{x}\) at \(x=4\).

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  • A. \(y = \frac{x}{4} + 1\)

Explanation

Compute \(f(4)=2\) and \(f'(x)=\frac{1}{2 \sqrt{x}}\), so \(f'(4)=\frac{1}{4}\). The line is \(y-f(4)=f'(4)(x-4)\), that is, \(y = \frac{x}{4} + 1\).

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Review the concept: Tangent line

The tangent line to the graph of \(f\) at the point \((a,f(a))\) is the line through that point with slope \(f^{\prime}(a)\). It is the best linear approximation of \(f\) near \(a\).

\[y-f(a)=f'(a)\,(x-a)\]

More practice problems: tangent line

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