Exercise · ZW-TYPES-OF-DISCONTINUITY-001 · ★☆☆ Basic

What type of discontinuity does \(f(x)=\dfrac{x^{2}-1}{x-1}\) have at \(x=1\)?

Choose one option.

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  • A. Removable

Explanation

The one-sided limits exist and are equal (the limit exists), but f(a) is undefined: it is a removable discontinuity. The hole can be "filled" by defining f(a) equal to the limit.

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Review the concept: Types of discontinuity

A function is discontinuous at \(a\) when some continuity condition fails. It can be removable, a jump, or infinite.

\[\lim_{x\to a^-}f(x)\neq\lim_{x\to a^+}f(x)\ \Rightarrow\ \text{jump discontinuity}\]

More practice problems: types of discontinuity

ZW-TYPES-OF-DISCONTINUITY-002 →