Exercise · ZW-TYPES-OF-DISCONTINUITY-008 · ★★★ Advanced
Let \(f(x)=\begin{cases}x+1 & x<0\\ x^{2}+2 & x\ge 0\end{cases}\). What type of discontinuity does it have at \(x=0\)?
Choose one option.
Show answer
- B. Jump
Exercise · ZW-TYPES-OF-DISCONTINUITY-008 · ★★★ Advanced
Choose one option.
The left-hand limit is \(1\) and the right-hand limit is \(2\), which differ even though \(f(0)=2\) exists. So the graph jumps: a jump discontinuity.
A function is discontinuous at \(a\) when some continuity condition fails. It can be removable, a jump, or infinite.
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