Exercise · ZW-TYPES-OF-DISCONTINUITY-008 · ★★★ Advanced

Let \(f(x)=\begin{cases}x+1 & x<0\\ x^{2}+2 & x\ge 0\end{cases}\). What type of discontinuity does it have at \(x=0\)?

Choose one option.

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  • B. Jump

Explanation

The left-hand limit is \(1\) and the right-hand limit is \(2\), which differ even though \(f(0)=2\) exists. So the graph jumps: a jump discontinuity.

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Review the concept: Types of discontinuity

A function is discontinuous at \(a\) when some continuity condition fails. It can be removable, a jump, or infinite.

\[\lim_{x\to a^-}f(x)\neq\lim_{x\to a^+}f(x)\ \Rightarrow\ \text{jump discontinuity}\]

More practice problems: types of discontinuity

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