Exercise · ZW-UNDETERMINED-COEFFICIENTS-009 · ★★★ Advanced

Find a particular solution of \(y''+2y'+y=e^{-t}\).

Choose one option.

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  • A. \(\tfrac12 t^2e^{-t}\)

Explanation

The root \(-1\) is double (\(r^2+2r+1=(r+1)^2\)), so \(e^{-t}\) and \(te^{-t}\) solve the homogeneous equation. Guess \(y_p=At^2e^{-t}\): \(y_p''+2y_p'+y_p=2Ae^{-t}\), and \(A=\tfrac12\).

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Review the concept: Undetermined coefficients

A method that finds a particular solution \(y_p\) of \(ay''+by'+cy=g(t)\) by guessing a function of the same type as \(g\), with coefficients \(A_i\) fixed by substitution.

\[y_p=t^{s}\,(A_0+A_1t+\cdots+A_nt^n)\,e^{kt}\]

More practice problems: undetermined coefficients

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