Exercise · ZW-ZERO-AND-POLE-003 · ★☆☆ Basic
What kind of singularity does \(\frac{1}{z^2+1}\) have at \(z=i\)?
Choose one option.
Show answer
- A. Simple pole
Explanation
Since \(z^2+1=(z-i)(z+i)\) and \(z+i\neq0\) at \(i\), the denominator has a simple zero: the function has a pole of order \(1\).
Review the concept: Zero and pole
A zero of order \(m\) of a holomorphic function \(f\) is a point \(z_0\) where \(f\) vanishes with multiplicity \(m\), with holomorphic quotient \(g\); a pole of order \(m\) is a point where \(1/f\) has such a zero.
\[f(z)=(z-z_0)^m\,g(z),\qquad g(z_0)\neq 0\]
More practice problems: zero and pole
- ZW-ZERO-AND-POLE-001 What is the order of the zero of z^3sin z at z=0?
- ZW-ZERO-AND-POLE-002 What is the order of the zero of 1-cos z at z=0?
- ZW-ZERO-AND-POLE-004 What is the order of the pole of (1)/(sin ^3 z) at z=0?
- ZW-ZERO-AND-POLE-005 What kind of singularity does (z)/(sin z) have at z=0?
- ZW-ZERO-AND-POLE-006 What is the order of the pole of (z^2-1)/((z-1)^3) at z=1?
- ZW-ZERO-AND-POLE-007 What is the order of the zero of e^z-1-z at z=0?
- ZW-ZERO-AND-POLE-008 What is the order of the pole of (1)/(z (e^z-1)) at z=0?
- ZW-ZERO-AND-POLE-009 f has a zero of order 2 and g one of order 5 at z_0. What does f/g have at z_0?