Exercise · ZW-ASYMPTOTES-003 · ★★☆ Intermediate

What are the asymptotes of \(f(x)=\frac{x^{2} + 1}{x^{2} - 4}\)?

Choose one option.

Show answer
  • D. Vertical: \(x=-2\), \(x=2\); horizontal: \(y=1\)

Explanation

Vertical asymptotes are where the denominator vanishes (without the numerator vanishing): x = -2, x = 2. The horizontal one comes from \(\lim_{x\to\infty}f(x)=1\), that is, y = 1.

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Review the concept: Asymptotes

An asymptote is a line the graph approaches without touching it. The line \(x=a\) is vertical if \(f\) tends to \(\pm\infty\) as \(x\to a\); the line \(y=L\) is horizontal if \(f(x)\to L\) as \(x\to\pm\infty\).

\[\begin{gathered}x=a:\ \lim_{x\to a}f(x)=\pm\infty\\ y=L:\ \lim_{x\to\pm\infty}f(x)=L\end{gathered}\]

More practice problems: asymptotes

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