Exercise · ZW-ASYMPTOTES-006 · ★★☆ Intermediate

What are the asymptotes of \(f(x)=\frac{x-1}{x^{2}-1}\)?

Choose one option.

Show answer
  • A. Vertical: \(x=-1\); horizontal: \(y=0\)

Explanation

Factoring, \(f(x)=\frac{1}{x+1}\) for \(x\neq 1\): x = 1 is a hole, not an asymptote. The vertical one is x = -1 and the horizontal one is y = 0.

Study Calculus in ZWMath →

Review the concept: Asymptotes

An asymptote is a line the graph approaches without touching it. The line \(x=a\) is vertical if \(f\) tends to \(\pm\infty\) as \(x\to a\); the line \(y=L\) is horizontal if \(f(x)\to L\) as \(x\to\pm\infty\).

\[\begin{gathered}x=a:\ \lim_{x\to a}f(x)=\pm\infty\\ y=L:\ \lim_{x\to\pm\infty}f(x)=L\end{gathered}\]

More practice problems: asymptotes

← ZW-ASYMPTOTES-005 ZW-ASYMPTOTES-007 →