Exercise · ZW-BIJECTIVE-FUNCTION-004 · ★☆☆ Basic
Which is the definition of surjectivity for \(f\colon A\to B\)?
Choose one option.
Show answer
- C. For each \(b\in B\) there is \(a\in A\) with \(f(a)=b\)
Explanation
Surjective requires every element of the codomain to be reached by at least one element of the domain. The cancellation condition defines injectivity, and the option with one common value for all \(a\) describes a constant function.
Review the concept: Bijective function
Function \(f\colon A\to B\) that is both injective and surjective, so each element of \(B\) corresponds to exactly one element of \(A\).
\[\forall b\in B\;\exists!\,a\in A\,(f(a)=b)\]
More practice problems: bijective function
- ZW-BIJECTIVE-FUNCTION-001 Which two properties must fcolon A→ B satisfy to be bijective?
- ZW-BIJECTIVE-FUNCTION-002 If fcolon A→ B is bijective, how many elements of A have image equal to a given b∈ B?
- ZW-BIJECTIVE-FUNCTION-003 What does it mean for fcolon A→ B to be injective?
- ZW-BIJECTIVE-FUNCTION-005 Let fcolon\1,2,3\→\a,b,c\ be injective. What can be concluded?
- ZW-BIJECTIVE-FUNCTION-006 Is fcolonℝ→ℝ, f(x)=x^3-x bijective?
- ZW-BIJECTIVE-FUNCTION-007 Which of these functions from ℤ to ℤ is bijective?
- ZW-BIJECTIVE-FUNCTION-008 If fcolon A→ B is bijective and |A|=5, what is |B|?
- ZW-BIJECTIVE-FUNCTION-009 Let fcolonℝ→ℝ, f(x)=x^3+x. Which statement is correct?