Exercise · ZW-CAUCHY-INTEGRAL-FORMULA-010 · ★★★ Advanced
For \(f(z)=(z+2)^3\), compute \(\displaystyle\frac{1}{2\pi i}\oint_{|z|=1}\frac{f(z)}{z}\,dz\), which equals the average of \(f\) over the circle.
Choose one option.
Show answer
- A. \(8\)
Exercise · ZW-CAUCHY-INTEGRAL-FORMULA-010 · ★★★ Advanced
Choose one option.
By the formula the result is \(f(0)=2^3=8\). The terms \(z,z^2,z^3\) of \(f\) average to zero over the circle, leaving only the constant term \(8\).
The Cauchy integral formula gives the value of a holomorphic function \(f\) at a point \(z_0\) inside a simple closed contour \(C\) by means of an integral of \(f\) over \(C\).