Exercise · ZW-CAUCHY-INTEGRAL-FORMULA-010 · ★★★ Advanced

For \(f(z)=(z+2)^3\), compute \(\displaystyle\frac{1}{2\pi i}\oint_{|z|=1}\frac{f(z)}{z}\,dz\), which equals the average of \(f\) over the circle.

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  • A. \(8\)

Explanation

By the formula the result is \(f(0)=2^3=8\). The terms \(z,z^2,z^3\) of \(f\) average to zero over the circle, leaving only the constant term \(8\).

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Review the concept: Cauchy integral formula

The Cauchy integral formula gives the value of a holomorphic function \(f\) at a point \(z_0\) inside a simple closed contour \(C\) by means of an integral of \(f\) over \(C\).

\[f(z_0)=\frac{1}{2\pi i}\oint_C\frac{f(z)}{z-z_0}\,dz\]

More practice problems: cauchy integral formula

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