Exercise · ZW-COMPLEX-TAYLOR-SERIES-005 · ★★☆ Intermediate

What if the centre is \(z_0=2\)? The radius for \(\dfrac1{z^2+1}\) is:

Choose one option.

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  • B. \(\sqrt5\)

Explanation

The radius is the distance to the nearest singularity: \(|2-i|=|2+i|=\sqrt{4+1}=\sqrt5\).

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Review the concept: Complex Taylor series

The Taylor series of a function \(f\) holomorphic on a disc \(|z-z_0|<R\) is the power series in \(z-z_0\), centred at \(z_0\), whose coefficients \(a_n\) come from the derivatives of \(f\) at \(z_0\).

\[f(z)=\sum_{n=0}^{\infty}a_n(z-z_0)^n,\quad a_n=\frac{f^{(n)}(z_0)}{n!}\]

More practice problems: complex taylor series

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