Exercise · ZW-COMPLEX-TAYLOR-SERIES-005 · ★★☆ Intermediate
What if the centre is \(z_0=2\)? The radius for \(\dfrac1{z^2+1}\) is:
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- B. \(\sqrt5\)
Exercise · ZW-COMPLEX-TAYLOR-SERIES-005 · ★★☆ Intermediate
Choose one option.
The radius is the distance to the nearest singularity: \(|2-i|=|2+i|=\sqrt{4+1}=\sqrt5\).
The Taylor series of a function \(f\) holomorphic on a disc \(|z-z_0|<R\) is the power series in \(z-z_0\), centred at \(z_0\), whose coefficients \(a_n\) come from the derivatives of \(f\) at \(z_0\).
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