Exercise · ZW-COMPLEX-TAYLOR-SERIES-006 · ★★☆ Intermediate
The coefficient of \((z-1)^3\) in the Taylor series of \(1/z\) at \(z_0=1\) is:
Choose one option.
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- C. \(-1\)
Exercise · ZW-COMPLEX-TAYLOR-SERIES-006 · ★★☆ Intermediate
Choose one option.
\(\tfrac1z=\tfrac1{1+(z-1)}=\sum(-1)^n(z-1)^n\), so \(a_3=-1\).
The Taylor series of a function \(f\) holomorphic on a disc \(|z-z_0|<R\) is the power series in \(z-z_0\), centred at \(z_0\), whose coefficients \(a_n\) come from the derivatives of \(f\) at \(z_0\).
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