Exercise · ZW-COMPLEX-TAYLOR-SERIES-009 · ★★★ Advanced

The coefficient of \(z^4\) in the Taylor series of \(z^2e^z\) at \(0\) is:

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  • B. \(\tfrac12\)

Explanation

\(z^2e^z=z^2(1+z+\tfrac{z^2}{2}+\cdots)\); the \(z^4\) term comes from \(z^2\cdot\tfrac{z^2}{2}\), so \(a_4=\tfrac12\).

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Review the concept: Complex Taylor series

The Taylor series of a function \(f\) holomorphic on a disc \(|z-z_0|<R\) is the power series in \(z-z_0\), centred at \(z_0\), whose coefficients \(a_n\) come from the derivatives of \(f\) at \(z_0\).

\[f(z)=\sum_{n=0}^{\infty}a_n(z-z_0)^n,\quad a_n=\frac{f^{(n)}(z_0)}{n!}\]

More practice problems: complex taylor series

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