Exercise · ZW-COMPLEX-TRIGONOMETRIC-FUNCTIONS-005 · ★☆☆ Basic

Simplify \(\sin(z+\pi)\).

Choose one option.

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  • A. \(-\sin z\)

Explanation

Since \(e^{i\pi}=-1\), \(e^{i(z+\pi)}=-e^{iz}\) and \(e^{-i(z+\pi)}=-e^{-iz}\); both terms change sign, so \(\sin(z+\pi)=-\sin z\).

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Review the concept: Complex trigonometric functions

The sine \(\sin z\) and cosine \(\cos z\) of a complex number \(z\) are the functions that extend the real ones through the complex exponential \(e^{iz}\).

\[\sin z=\frac{e^{iz}-e^{-iz}}{2i},\qquad \cos z=\frac{e^{iz}+e^{-iz}}{2}\]

More practice problems: complex trigonometric functions

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