Exercise · ZW-COMPLEX-TRIGONOMETRIC-FUNCTIONS-009 · ★★★ Advanced

What are all the zeros of \(\sin z\) in \(\mathbb{C}\)?

Choose one option.

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  • A. Only \(z=k\pi\) with \(k\in\mathbb{Z}\)

Explanation

\(\sin z=0\) is equivalent to \(e^{2iz}=1\), that is \(2iz=2\pi i k\) and \(z=k\pi\). No new zeros appear off the real axis.

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Review the concept: Complex trigonometric functions

The sine \(\sin z\) and cosine \(\cos z\) of a complex number \(z\) are the functions that extend the real ones through the complex exponential \(e^{iz}\).

\[\sin z=\frac{e^{iz}-e^{-iz}}{2i},\qquad \cos z=\frac{e^{iz}+e^{-iz}}{2}\]

More practice problems: complex trigonometric functions

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