Exercise · ZW-COMPLEX-TRIGONOMETRIC-FUNCTIONS-006 · ★★☆ Intermediate

Compute \(\sin\!\left(\dfrac{\pi}{2}+i\ln 2\right)\).

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  • B. \(\dfrac{5}{4}\)

Explanation

\(\sin(x+iy)=\sin x\cosh y+i\cos x\sinh y\). With \(x=\pi/2\) this gives \(\cosh(\ln 2)=\frac{2+1/2}{2}=\frac54\), since \(\cos(\pi/2)=0\).

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Review the concept: Complex trigonometric functions

The sine \(\sin z\) and cosine \(\cos z\) of a complex number \(z\) are the functions that extend the real ones through the complex exponential \(e^{iz}\).

\[\sin z=\frac{e^{iz}-e^{-iz}}{2i},\qquad \cos z=\frac{e^{iz}+e^{-iz}}{2}\]

More practice problems: complex trigonometric functions

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