Exercise · ZW-CONDITIONAL-PROBABILITY-004 · ★☆☆ Basic

If \(P(A)=0.6\), \(P(B)=0.4\) and \(P(A\cup B)=0.7\), what is \(P(A\mid B)\)?

Choose one option.

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  • A. 0.75

Explanation

By the addition rule, \(P(A\cap B)=0.6+0.4-0.7=0.3\). Then \(P(A\mid B)=0.3/0.4=0.75\). Dividing by \(P(A\cup B)\) would give 0.43, which is something else.

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Review the concept: Conditional probability

The conditional probability of \(A\) given \(B\), \(P(A\mid B)\), is the probability that \(A\) occurs when \(B\) is already known to have occurred; it is computed within the space reduced to \(B\).

\[P(A\mid B)=\frac{P(A\cap B)}{P(B)},\qquad P(B)>0\]

More practice problems: conditional probability

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