Exercise · ZW-CONDITIONAL-PROBABILITY-006 · ★★☆ Intermediate

Two cards are drawn from a 52-card deck without replacement. What is the probability that both are kings?

Choose one option.

Show answer
  • D. 1/221

Explanation

\(P(K_1)P(K_2\mid K_1)=\frac{4}{52}\cdot\frac{3}{51}=\frac{1}{221}\). The value 1/169 would assume the card is replaced.

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Review the concept: Conditional probability

The conditional probability of \(A\) given \(B\), \(P(A\mid B)\), is the probability that \(A\) occurs when \(B\) is already known to have occurred; it is computed within the space reduced to \(B\).

\[P(A\mid B)=\frac{P(A\cap B)}{P(B)},\qquad P(B)>0\]

More practice problems: conditional probability

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