Exercise · ZW-CONSTRUCTION-OF-THE-REALS-009 · ★★☆ Intermediate
Why is \( \mathbb{Q} \) not complete while \( \mathbb{R} \) is?
Choose one option.
Show answer
- C. Because there are Cauchy sequences of rationals with no rational limit
Exercise · ZW-CONSTRUCTION-OF-THE-REALS-009 · ★★☆ Intermediate
Choose one option.
For example, the decimal approximations of \( \sqrt{2} \) form a Cauchy sequence of rationals with no limit in \( \mathbb{Q} \).
The real numbers \( \mathbb{R} \) form a complete ordered field extending \( \mathbb{Q} \), in which every bounded Cauchy sequence converges. They are built from \( \mathbb{Q} \) using Dedekind cuts or Cauchy sequences.
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