Exercise · ZW-CONVERGENCE-WITH-LIPSCHITZ-GRADIENT-010 · ★★★ Advanced
Let \( f(x)=2x^2 \) on \( \mathbb{R} \), with \( x_0=1 \) and step \( t=1/L \). What is \( x_1 \)?
Choose one option.
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- D. \( 0 \)
Exercise · ZW-CONVERGENCE-WITH-LIPSCHITZ-GRADIENT-010 · ★★★ Advanced
Choose one option.
Here \( \nabla f(x)=4x \), so \( L=4 \) and \( t=1/4 \). Then \( x_1=1-\frac{1}{4}\cdot 4=0 \). Using \( L=2 \) would give \( x_1=-1 \), a typical mistake.
Result guaranteeing that gradient descent with a suitable step size converges for differentiable functions whose gradient \( \nabla f \) is Lipschitz continuous with constant \( L \).