With \((1-t)+it\) we get \(\gamma(0)=1\) and \(\gamma(1)=i\), and it is linear in \(t\) (derivative \(-1+i\neq0\)). The option \(t+i(1-t)\) runs from \(i\) to \(1\).
A smooth curve \(\gamma\) is a function from a real interval \([a,b]\) into \(\mathbb{C}\) with continuous, nonzero derivative; a contour is a finite chain of smooth curves joined end to end.