Exercise · ZW-CURVE-AND-CONTOUR-008 · ★★★ Advanced

Is \(\gamma(t)=t^3+it^3\) a smooth curve on \([-1,1]\)? Its image is a segment.

Choose one option.

Show answer
  • B. No: \(\gamma'(0)=0\), and the definition requires a nonzero derivative

Explanation

A continuous \(\gamma'\) is not enough: \(\gamma'(t)=3t^2(1+i)\) vanishes at \(t=0\). The image is a segment, but this parametrization is not smooth; \(\gamma(t)=t+it\) traces the same segment and is smooth.

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Review the concept: Curve and contour

A smooth curve \(\gamma\) is a function from a real interval \([a,b]\) into \(\mathbb{C}\) with continuous, nonzero derivative; a contour is a finite chain of smooth curves joined end to end.

\[\gamma(t)=x(t)+i\,y(t),\qquad a\le t\le b\]

More practice problems: curve and contour

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