Exercise · ZW-DIRECTIONAL-DERIVATIVE-005 · ★★☆ Intermediate

A point at \((1,1)\) moves toward \((4,5)\). Compute the rate of change of \(f(x,y)=x^2y+y\) in that direction.

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  • C. \(\tfrac{14}{5}\)

Explanation

The direction is \(\langle3,4\rangle/5\) and \(\nabla f(1,1)=\langle2xy,x^2+1\rangle=\langle2,2\rangle\). Then \(D_{\mathbf{u}}f=\tfrac{6+8}{5}=\tfrac{14}{5}\).

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Review the concept: Directional derivative

The directional derivative \(D_{\mathbf{u}}f\) of \(f\) at a point \(\mathbf{x}_0\), along a unit vector \(\mathbf{u}\), is the rate of change of \(f\) moving from \(\mathbf{x}_0\) in the direction of \(\mathbf{u}\).

\[D_{\mathbf{u}}f(\mathbf{x}_0)=\lim_{h\to0}\frac{f(\mathbf{x}_0+h\mathbf{u})-f(\mathbf{x}_0)}{h}\]

More practice problems: directional derivative

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