Exercise · ZW-EQUIVALENCE-RELATION-010 · ★★★ Advanced

Is every symmetric and transitive relation on \(A\) an equivalence relation?

Choose one option.

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  • C. No: \(R=\{(1,1)\}\) on \(\{1,2\}\) is symmetric and transitive but not reflexive, because \((2,2)\notin R\)

Explanation

Reflexivity does not follow from the other two. On \(\{1,2\}\), the relation \(\{(1,1)\}\) has no chains that violate symmetry or transitivity, yet \(2\) is not related to itself.

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Review the concept: Equivalence relation

A binary relation \(R\) on \(A\) that is reflexive, symmetric and transitive. It groups the elements of \(A\) that behave alike with respect to some property.

\[\forall a\in A\,(a\,R\,a)\ \wedge\ \forall a,b\in A\,(aRb \Rightarrow bRa)\ \wedge\\ \forall a,b,c\in A\,(aRb\wedge bRc\Rightarrow aRc)\]

More practice problems: equivalence relation

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