Exercise · ZW-GREENS-THEOREM-009 · ★★★ Advanced
Let \(C\) be the counterclockwise boundary of a region \(D\). Which of these line integrals over \(C\) gives the area of \(D\)?
Choose one option.
A \(\oint_C y\,dx\) B \(\oint_C x\,dy\) C \(\oint_C x\,dx+y\,dy\) D \(\oint_C y\,dy\)
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Explanation With \(P=0\), \(Q=x\) we get \(Q_x-P_y=1\), so \(\oint_C x\,dy=\iint_D dA\). The option \(\oint_C y\,dx\) gives the negative of the area.
Green's theorem equates the circulation of a field \(\mathbf F=\langle P,Q\rangle\) along a simple closed curve \(C\), counterclockwise, with a double integral over its region \(D\), with respect to area \(A\).
\[\oint_C P\,dx+Q\,dy=\iint_D\left(\frac{\partial Q}{\partial x}-\frac{\partial P}{\partial y}\right)dA\]
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