Exercise · ZW-IMAGE-AND-PREIMAGE-005 · ★★☆ Intermediate

Let \(f(x)=x^2\) from \(\mathbb{R}\) to \(\mathbb{R}\). What is \(f([-1,2])\)?

Choose one option.

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  • C. \([0,4]\)

Explanation

On \([-1,2]\) the square equals 0 at \(x=0\) and reaches \(2^2=4\) at \(x=2\); since \(x^2\) is continuous there, the image is the interval \([0,4]\). No negative value can appear, and 0 does appear.

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Review the concept: Image and preimage

Given \(f\colon A\to B\), the image of \(X\subseteq A\) is the set of values \(f(x)\) with \(x\in X\), and the preimage of \(Y\subseteq B\) is the set of \(a\in A\) whose value lies in \(Y\).

\[f(X)=\{f(x)\colon x\in X\},\qquad f^{-1}(Y)=\{a\in A\colon f(a)\in Y\}\]

More practice problems: image and preimage

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