Exercise · ZW-IMAGE-AND-PREIMAGE-007 · ★★☆ Intermediate

Let \(f\colon A\to B\) and \(X_1,X_2\subseteq A\). Which statement about images is correct?

Choose one option.

Show answer
  • A. \(f(X_1\cup X_2)=f(X_1)\cup f(X_2)\)

Explanation

The image of a union is the union of the images, since each value comes from a point in \(X_1\) or in \(X_2\). For intersections and differences equality fails: for \(f(x)=x^2\), \(X_1=\{-1\}\) and \(X_2=\{1\}\), the intersection of the sets is empty but \(f(X_1)\cap f(X_2)=\{1\}\).

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Review the concept: Image and preimage

Given \(f\colon A\to B\), the image of \(X\subseteq A\) is the set of values \(f(x)\) with \(x\in X\), and the preimage of \(Y\subseteq B\) is the set of \(a\in A\) whose value lies in \(Y\).

\[f(X)=\{f(x)\colon x\in X\},\qquad f^{-1}(Y)=\{a\in A\colon f(a)\in Y\}\]

More practice problems: image and preimage

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