Exercise · ZW-INTERMEDIATE-VALUE-THEOREM-011 · ★☆☆ Basic
Let \(f(x)=x^3-x-1\) on \([1,2]\). Since \(f(1)=-1\) and \(f(2)=5\), what does the intermediate value theorem guarantee?
Choose one option.
A That \(f\) is increasing on \([1,2]\) B That there is \(c\in[1,2]\) with \(f(c)=0\) C That the root is exactly \(c=1.5\) D That there is \(c\) with \(f(c)=7\)
Show answer B. That there is \(c\in[1,2]\) with \(f(c)=0\)
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Explanation Zero lies between \(-1\) and \(5\), so some \(c\) attains it; the theorem does not say where it is or that \(f\) is monotone, and \(7>5\) is out of range .
If \(f\) is continuous on \([a,b]\) and \(N\) lies between \(f(a)\) and \(f(b)\), there is some \(c\in(a,b)\) with \(f(c)=N\).