Exercise · ZW-INTERMEDIATE-VALUE-THEOREM-012 · ★☆☆ Basic

For \(f(x)=x^2\) on \([0,3]\), which \(c\in[0,3]\) satisfies \(f(c)=5\)?

Choose one option.

Show answer
  • C. \(c=\sqrt5\)

Explanation

We need \(c^2=5\) with \(c\ge0\), that is \(c=\sqrt5\approx2.24\), which lies in \([0,3]\) because \(0<5<9\).

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Review the concept: Intermediate value theorem

If \(f\) is continuous on \([a,b]\) and \(N\) lies between \(f(a)\) and \(f(b)\), there is some \(c\in(a,b)\) with \(f(c)=N\).

\[f\ \text{continuous on }[a,b],\ f(a)

More practice problems: intermediate value theorem

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