Exercise · ZW-INTERMEDIATE-VALUE-THEOREM-014 · ★☆☆ Basic

Let \(f(x)=x^2-3\) on \([1,2]\). After evaluating the midpoint \(1.5\), on which interval is a root guaranteed?

Choose one option.

Show answer
  • D. \([1.5,2]\)

Explanation

\(f(1.5)=-0.75<0\) and \(f(2)=1>0\): the sign changes on \([1.5,2]\), where the theorem ensures a root (bisection).

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Review the concept: Intermediate value theorem

If \(f\) is continuous on \([a,b]\) and \(N\) lies between \(f(a)\) and \(f(b)\), there is some \(c\in(a,b)\) with \(f(c)=N\).

\[f\ \text{continuous on }[a,b],\ f(a)

More practice problems: intermediate value theorem

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