Exercise · ZW-INVERSE-MATRIX-005 · ★☆☆ Basic

Solve \(A\mathbf{x}=\mathbf{b}\) using the inverse, with \(A=\begin{pmatrix}1 & 2 \\ 3 & 5\end{pmatrix}\) and \(\mathbf{b}=(1,2)^T\).

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  • B. \((x,y)=(-1,\,1)\)

Explanation

Here \(\det A=-1\) and \(A^{-1}=\begin{pmatrix}-5 & 2\\ 3 & -1\end{pmatrix}\). Then \(\mathbf{x}=A^{-1}\mathbf{b}=(-5+4,\;3-2)=(-1,1)\). Substituting: \(-1+2=1\) and \(-3+5=2\).

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Review the concept: Inverse matrix

The inverse of a square matrix \(A\) is the matrix \(A^{-1}\) that gives the identity \(I\) when multiplied by \(A\) on either side; if it exists, \(A\) is called invertible.

\[AA^{-1}=A^{-1}A=I\]

More practice problems: inverse matrix

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