Exercise · ZW-INVERSE-MATRIX-008 · ★★☆ Intermediate

If \(A\) is an invertible \(2\times2\) matrix, what is \((3A)^{-1}\)?

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  • D. \(\frac13A^{-1}\)

Explanation

Since \((3A)\left(\tfrac13A^{-1}\right)=AA^{-1}=I\), the inverse of a scalar multiple \(cA\) is \(\tfrac1cA^{-1}\). The scalar is inverted, not multiplied.

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Review the concept: Inverse matrix

The inverse of a square matrix \(A\) is the matrix \(A^{-1}\) that gives the identity \(I\) when multiplied by \(A\) on either side; if it exists, \(A\) is called invertible.

\[AA^{-1}=A^{-1}A=I\]

More practice problems: inverse matrix

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