Exercise · ZW-LHOPITALS-RULE-008 · ★☆☆ Basic

Compute \(\lim_{x\to 2}\,\frac{x^{2} - 4}{x - 2}\).

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  • D. \(4\)

Explanation

Substituting gives 0/0; differentiating gives \(\frac{2x}{1}\), which at \(x=2\) equals \(4\).

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Review the concept: L'Hôpital's rule

Rule that computes limits of quotients in indeterminate form \(\frac{0}{0}\) or \(\frac{\infty}{\infty}\) by differentiating numerator and denominator separately.

\[\lim_{x\to a}\frac{f(x)}{g(x)}=\lim_{x\to a}\frac{f'(x)}{g'(x)}\]

More practice problems: l'hôpital's rule

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