Exercise · ZW-LHOPITALS-RULE-012 · ★☆☆ Basic

Compute \(\displaystyle\lim_{x\to2}\frac{x^2-4}{x-2}\).

Choose one option.

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  • A. \(4\)

Explanation

It is \(0/0\). Differentiating: \(\frac{2x}{1}\to4\), matching the factorization \((x-2)(x+2)/(x-2)\).

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Review the concept: L'Hôpital's rule

Rule that computes limits of quotients in indeterminate form \(\frac{0}{0}\) or \(\frac{\infty}{\infty}\) by differentiating numerator and denominator separately.

\[\lim_{x\to a}\frac{f(x)}{g(x)}=\lim_{x\to a}\frac{f'(x)}{g'(x)}\]

More practice problems: l'hôpital's rule

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