Exercise · ZW-LINES-AND-PLANES-IN-SPACE-002 · ★☆☆ Basic
A line passes through \((1,0,2)\) with direction \(\langle3,-1,4\rangle\). What are its parametric equations ?
Choose one option.
A \(x=1+3t,\ y=-t,\ z=2+4t\) B \(x=3+t,\ y=-1,\ z=4+2t\) C \(x=1+3t,\ y=t,\ z=2+4t\) D \(x=3t,\ y=-t,\ z=4t\)
Show answer A. \(x=1+3t,\ y=-t,\ z=2+4t\)
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Explanation Add to the starting point \(t\) times the direction vector in each coordinate: \((1,0,2)+t\langle3,-1,4\rangle\).
A line in space is determined by a point \(\mathbf r_0\) and a direction vector \(\mathbf d\); a plane, by a point \(\mathbf r_0\) and a normal vector \(\mathbf n\) perpendicular to it.
\[\begin{aligned}\mathbf r(t)&=\mathbf r_0+t\,\mathbf d\\\mathbf n\cdot(\mathbf r-\mathbf r_0)&=0\end{aligned}\]
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