Exercise · ZW-LINES-AND-PLANES-IN-SPACE-008 · ★★☆ Intermediate

What is the relation between the line \((1,1,1)+t\langle2,-1,3\rangle\) and the plane \(4x-2y+6z=5\)?

Choose one option.

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  • B. The line is perpendicular to the plane

Explanation

The plane's normal is \(\langle4,-2,6\rangle=2\langle2,-1,3\rangle\), proportional to the direction vector. A line whose direction equals the normal is perpendicular to the plane.

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Review the concept: Lines and planes in space

A line in space is determined by a point \(\mathbf r_0\) and a direction vector \(\mathbf d\); a plane, by a point \(\mathbf r_0\) and a normal vector \(\mathbf n\) perpendicular to it.

\[\begin{aligned}\mathbf r(t)&=\mathbf r_0+t\,\mathbf d\\\mathbf n\cdot(\mathbf r-\mathbf r_0)&=0\end{aligned}\]

More practice problems: lines and planes in space

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