Exercise · ZW-LIOUVILLE-THEOREM-009 · ★★★ Advanced
Let \(f\) be entire with \(|f(z)|\ge1\) for all \(z\). Which bounded entire function results?
Choose one option.
Show answer
- C. \(g(z)=1/f(z)\), with \(|g|\le1\)
Exercise · ZW-LIOUVILLE-THEOREM-009 · ★★★ Advanced
Choose one option.
Since \(f\) never vanishes, \(1/f\) is entire, and \(|1/f|\le1\). By Liouville \(1/f\) is constant, hence so is \(f\).
Liouville's theorem says that every entire function \(f\), that is, holomorphic on the whole plane, bounded by a constant \(M\) is constant.