Exercise · ZW-LIOUVILLE-THEOREM-010 · ★★★ Advanced
Let \(f\) be entire with \(f(z+1)=f(z)\) and \(f(z+i)=f(z)\) for all \(z\). What follows?
Choose one option.
Show answer
- A. \(f\) is constant
Exercise · ZW-LIOUVILLE-THEOREM-010 · ★★★ Advanced
Choose one option.
All values of \(f\) repeat on the square \([0,1]\times[0,1]\), which is compact, so \(f\) is bounded. By Liouville it is constant. \(e^{2\pi iz}\) does not satisfy \(f(z+i)=f(z)\).
Liouville's theorem says that every entire function \(f\), that is, holomorphic on the whole plane, bounded by a constant \(M\) is constant.