Exercise · ZW-MEAN-VALUE-THEOREM-014 · ★★☆ Intermediate

For \(f(x)=e^x\) on \([0,1]\), which \(c\) satisfies \(f'(c)=f(1)-f(0)\)?

Choose one option.

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  • C. \(c=\ln(e-1)\)

Explanation

We need \(e^c=e-1\), so \(c=\ln(e-1)\approx0.541\), which lies in \((0,1)\).

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Review the concept: Mean value theorem

If \(f\) is continuous on \([a,b]\) and differentiable on \((a,b)\), there is a \(c\in(a,b)\) such that the slope of the tangent at \(c\) equals the slope of the secant line joining \((a,f(a))\) and \((b,f(b))\).

\[f'(c)=\frac{f(b)-f(a)}{b-a}\]

More practice problems: mean value theorem

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