Exercise · ZW-MEAN-VALUE-THEOREM-015 · ★☆☆ Basic

For \(f(x)=\ln x\) on \([1,e]\), what is the point \(c\) of the mean value theorem?

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  • C. \(c=e-1\)

Explanation

The chord slope is \(\frac{1-0}{e-1}\) and \(f'(c)=\frac1c\), so \(c=e-1\approx1.718\), which is in \((1,e)\).

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Review the concept: Mean value theorem

If \(f\) is continuous on \([a,b]\) and differentiable on \((a,b)\), there is a \(c\in(a,b)\) such that the slope of the tangent at \(c\) equals the slope of the secant line joining \((a,f(a))\) and \((b,f(b))\).

\[f'(c)=\frac{f(b)-f(a)}{b-a}\]

More practice problems: mean value theorem

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